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Calculaţi: (x + 2)2 – 3(2 – x)(2 + x).

Răspuns :

(x+2)²-3(2-x)(2+x)=

=x²+2x×2+2²-3(2²-x²)=

=x²+4x+4-3(4-x²)=

=x²+4x+4-12+3x²=4x²+4x-8

Răspuns:

[tex](x+2)^{2} -3 * (2-x)(2+x)=\\\\x^{2}+2 * x * 2+2^{2}-3(2^{2}-x^{2} )=\\\\x^{2} +4x+4-3(4-x^{2})=\\\\x^{2} +4x+4-12+3x^{2} =\\\\4x^{2} +4x-8\\[/tex]