Răspuns:
Explicație pas cu pas:
[tex]x=(5\sqrt{2}-\sqrt{18})^{2}=(5\sqrt{2}-\sqrt{9*2} )^{2}=(5\sqrt{2}-3\sqrt{2})^{2}=(2\sqrt{2} )^{2}=2^{2}*(\sqrt{2})^{2}=4*2=8.\\ y=|6-4\sqrt{3}|+\sqrt{(10\sqrt{2}-2)(10\sqrt{2}+2)}=|6-\sqrt{4^{2}*3}|+\sqrt{(10\sqrt{2})^{2}-2^{2}}=|\sqrt{6^{2}}-\sqrt{48} |+\sqrt{100*2-4}=| \sqrt{48}- \sqrt{6^{2}}|+\sqrt{196}=4\sqrt{3}-6+14=4\sqrt{3}+8.\\[/tex]
cred la x ai perdut termenul -4√3, atunci x=8-4√3.
[tex]b)~~mg=\sqrt{x*y}=\sqrt{(8-4\sqrt{3})(8+\sqrt{3})}=\sqrt{8^{2}-(4\sqrt{3})^{2} }=\sqrt{64-48}=\sqrt{16}=4.[/tex]
