Răspuns:
Explicație pas cu pas:
AB=baza mica=8cm
CD=baza mare =16 cm
BC⊥CD BC=6 cm
Construim AE⊥CD se formeaza ΔAED
AE=BC=6 cm
ED=CD=AB=16-8 =8 cm
AD²=ED²+AE² AD²=64+36=100 AD=10 cm
Aabcd=(16+8)×6/2=24×3=72 cm²
M=AD∩BC Cf teoremei fundamentale a asemanarii
MB/MC=MA/MD=AB/CD=8/16=1/2 ⇒ MB=BC=6 cm MC=12 cm
MD=2AD=2×10=20 cm
Pmcd=MC+MD+CD=12+20+16=28+20=48 cm
