3. Cum vad eu problema
[tex]\frac{x}{y} =0,2 => \frac{x}{y} =\frac{2}{10} =>10x=2y=>x=\frac{2y}{10}[/tex]
[tex]\frac{5y-2x}{5y+2x}=\frac{5y-2(\frac{2y}{10}) }{5y+2(\frac{2y}{10}) } =\frac{5y-\frac{4y}{10} }{5y+\frac{4y}{10} }=\frac{\frac{46y}{10} }{\frac{54y}{10} } =\frac{46y}{54y} =\frac{46}{54} =\frac{23}{27}[/tex]
4.
[tex]\frac{20}{100} *2750=2*275=550[/tex]
