Răspuns: 3³⁶
[tex]\it b) \: [(2^{3})^{5}+25^{3}-7^{35} : 7^{20}]:(2^{15 }-7^{15} +5^{6})\cdot3^{36}\\\\\it (2^{3\cdot5}+(5^{2})^{3}-7^{35-20}):(2^{15 }-7^{15} +5^{6})\cdot3^{36}\\\\\it (2^{15}+5^{2\cdot3}-7^{15}):(2^{15 }-7^{15} +5^{6})\cdot3^{36}\\\\\it (2^{15}+5^{6}-7^{15}):(2^{15 }-7^{15} +5^{6})\cdot3^{36}\\\\\it (2^{15}-7^{15}+5^{6}):(2^{15 }-7^{15} +5^{6})\cdot3^{36}\\\\\it 1\cdot3^{36} = \boxed{\it3^{36}}[/tex]
