Acid monocarboxilic saturat - CnH2nO2
M CnH2nO2 = 12n+2n+32 = 14n+32
14n + 32 g acid .... 32 g O2
100 g acid ............. 53,33 O2
[tex] \frac{14n + 32}{100} = \frac{32}{53.33} \\ 53.33(14n + 32) = 3200 \\ 746.62n + 1706.56 = 3200 \\ 746.62n = 1493.44 \\ n = 2[/tex]
C2H4O2 - acid acetic
Răspuns:formula generala a acizilor monocarboxilici saturati CnH2nO2 masa molara=12n+2n+32=14n+32 la 100g acid................53,33 g O Xg acid.........................32 g O X=32.100/53,33=60 g/mol se egaleaza 14n+32=60 14n=60-32=28 n=28/14=2 C2H4O2 CH3-COOH acid etanoic{acid acetic}
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