[tex]\it m_a=\dfrac{\sqrt9+\sqrt{25}+\sqrt{16}}{3} =\dfrac{3+5+4}{3}=\dfrac{12}{3}=4[/tex]
Răspuns:
[tex]ma=\dfrac{ \sqrt{9}+\sqrt{25}+ \sqrt{16}}{3}\\\\ ma=\dfrac{3 + 5 + 4}{3}\\\\ ma=\dfrac{\not{12}}{\not3}\\ \\ \boxed{ma=4}\\\\\text{observatie:}\\\\\sqrt{9}=\sqrt{{3}^{2}}= 3\\\\\sqrt{25}=\sqrt{{5}^{2}}=5\\\\ \sqrt{16}=\sqrt{ {4}^{2}} = 4[/tex]
