[tex]\it 5)\\ \\ \sqrt{0,25}=\sqrt{0,5^2}=0,5\\ \\ \sqrt{0,81}=\sqrt{0,9^2}=0,9\\ \\ \sqrt{2,56}=\sqrt{1,6^2}=1,6\\ \\ \sqrt{6,76}=\sqrt{2,6^2}=2,6\\ \\ \sqrt{0,0225}=\sqrt{0,15^2}=0,15[/tex]
[tex]\it 6)\\ \\ a=2\Big(\dfrac{3^2+4^2}{5^2}+\dfrac{25^2-15^2}{20^2}\Big)=2\Big(\dfrac{25}{25}+\dfrac{400}{400}\Big)=2(1+1)=2\cdot2=4\\ \\ \\ \sqrt a=\sqrt4=2[/tex]
