Răspuns:
a.0,1,2,3,4
b.20, 21, 22, 23, 24
a. x:7=8 rest 3
x=7×8+3=56+3=59
b. 62:7=8 rest 6
deci 62 este cel mai mare nr natural care implineste conditia
a. 0,1,2,3
b. resturi posibile=0,1,2,3
x:4=1 rest 1
x=4×1+1=5
y:4=2 rest 2
y=4×2+2=10
z:4= 3 rest 3
z=4×3+3=15
c. x:4=1 rest 2
x=4+2=6
