Salut.
[tex]a = [1 - 1,(6)]^{2} \cdot 1,5 - 1,8(3)[/tex]
[tex]\displaystyle{a= (1 - \frac{16-1}{9})^{2} \cdot \frac{15}{10} - \frac{183-18}{90} }[/tex]
[tex]\displaystyle{ a =( \frac{9}{9}-\frac{15}{9})^{2} \cdot \frac{15}{10} - \frac{165}{90}}[/tex]
[tex]\displaystyle{ a = (\frac{-6}{9})^{2} \cdot \frac{3}{2}-\frac{11}{6} }[/tex]
[tex]\displaystyle{ a = (\frac{-2}{3})^{2} \cdot \frac{9}{6}-\frac{11}{6} }[/tex]
[tex]\displaystyle{a = \frac{4}{9} \cdot \frac{9}{6} - \frac{11}{6} }[/tex]
[tex]\displaystyle{a=\frac{4}{6}-\frac{11}{6} }[/tex]
[tex]\boxed{a=\frac{-7}{6}}[/tex]
- Lumberjack25
