Scuze de confuzie....
c)
a L a L 2a L
C4H10 ----> C4H6 + 2H2
22,4 22,4 2x22,4
b L b L
C4H10 ---> C4H10 netransformat
22,4 22,4
a + b = V L C4H10 intrat in reactie
3a + b = 2,5V L amesteg de gaze rezultate
=>
3a + b = 2,5V (-)
a + b = V
-------------------------
2a + / = 1,5V L => a = 0,75V L C4H10 transformat
=>
0,75V + b = V => b = 0,25V L C4H10 netransformat
n = V.practic(transformat)x100/V.total.intrat
= 0,75Vx100/V = 75%
