Răspuns:
[tex]a = \sqrt{(3 \sqrt{3} - 4 \sqrt{2} ) {}^{2} } - \sqrt{(2 \sqrt{3} - 3 \sqrt{2}) {}^{2} } = 4 \sqrt{2} - 3 \sqrt{3} - (3 \sqrt{2} - 2 \sqrt{3} ) = 4 \sqrt{2} - 3 \sqrt{3} - 3 \sqrt{2} + 2 \sqrt{3} = \sqrt{2} - \sqrt{3} [/tex]
[tex]b = | \sqrt{3} - 2 \sqrt{2} | + | \sqrt{2} - 2 \sqrt{3} | = 2 \sqrt{2} - \sqrt{3} + 2 \sqrt{3} - \sqrt{2} = \sqrt{2} + \sqrt{3} [/tex]
[tex]media \: aritmetrica \: = \frac{a + b}{2} = \frac{ (\sqrt{2} - \sqrt{3} ) + ( \sqrt{2} + \sqrt{3}) }{2} = \frac{ \sqrt{2} - \sqrt{3} + \sqrt{2} + \sqrt{3} }{2} = \frac{2 \sqrt{2} }{2} = \sqrt{2} [/tex]
Raspuns final : C.
Sper ca te-am ajutat :)
