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ajutor urgent A) 35la puterea n+3 • 7la puterea n+1• 125 la puterea n+9=pp​

Răspuns :

Răspuns:

= (5²ⁿ⁺¹⁵•7ⁿ⁺²)² = patrat perfect

Explicație pas cu pas:

35ⁿ⁺³• 7ⁿ⁺¹• 125ⁿ⁺⁹ = patrat perfect ?

35ⁿ⁺³ = (5•7)ⁿ⁺³ = (5•7)³•(5•7)ⁿ

7ⁿ⁺¹ = 7•7ⁿ

125ⁿ⁺⁹ = (5³)ⁿ⁺⁹ = 5³ⁿ⁺²⁷ = 5²⁷•5³ⁿ

35ⁿ⁺³• 7ⁿ⁺¹• 125ⁿ⁺⁹ = 5³•7³•5ⁿ •7ⁿ •7•7ⁿ•5²⁷•5³ⁿ =

= 5³⁺²⁷•5ⁿ⁺³ⁿ•7³⁺¹•7ⁿ⁺ⁿ = 5³⁰•5⁴ⁿ•7⁴•7²ⁿ =

= (5¹⁵•5²ⁿ•7²•7ⁿ)² = (5²ⁿ⁺¹⁵•7ⁿ⁺²)² = patrat perfect