Explicație:
A ball of mass 8 kg is dropped from a height of 10 m. What is the velocity with which it strikes the ground?
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First Method
Just Apply Third Equation Of Motion
v 2 - u 2 = 2as
a= acceleration
s= displacement
u=initial velocity
v=final velocity
If the body is freely falling under gravity then this equation can be modified as
v 2 - u 2 = 2gh
h= height from which body is dropped
g=9.8 m/s 2
Now Come To Your Question According to you question body is dropped from height of 10m so we can consider its initial velicity as zero
h=10m
u=0
g=acceleration due to gravity on earth which is equal to 9.8 m/s 2
Now put the values of { height, initial velocity and acceleration due to gravity in third equation of motion }
i.e
v 2 - u 2 = 2gh
v 2 - 0 = 2×9.8×10
v 2 = 196
v=14m/s
Hence the velocity with which it strikes the ground is 14m/s
Second Method
Now this question can also be solved by another way
mgh = 1/2×mv 2
wher m is the mass of the body v is velocity and g is acceleration due to gravity and h is the height
2gh=v 2
2×9.8×10 = v 2
v 2 = 196
v= 14m/s
By any way you solve there is no role of mass here
