[tex]\bf \dfrac{x+3}{2}+ \dfrac{2x-1}{3} =1 \:\:\:|\cdot6[/tex]
[tex]\bf3(x+3) +2(2x-1)=6[/tex]
[tex]\bf 3x+9 + 4x-2=6[/tex]
[tex]\bf 7x +9-2=6[/tex]
[tex]\bf7x+7 = 6[/tex]
[tex]\bf7x= 6-7[/tex]
[tex]\bf 7x = -1[/tex]
[tex]\boxed{\bf x = -\dfrac{1}{7}}[/tex]
