Răspuns:
1
Explicație pas cu pas:
[tex](\dfrac{3^\sqrt{5} }{3^\sqrt{2}})^{\sqrt{5}+\sqrt{2}} *(\dfrac{3^\sqrt{7} }{3^\sqrt{10}})^{\sqrt{7}+\sqrt{10}} =(3^{\sqrt{5}-\sqrt{2}})^{\sqrt{5}+\sqrt{2}}*(3^{\sqrt{7}-\sqrt{10}})^{\sqrt{7}+\sqrt{10}}=3^{(\sqrt{5}-\sqrt{2})(\sqrt{5}+\sqrt{2})}*[/tex][tex]*3^{(\sqrt{7}-\sqrt{10})(\sqrt{7}+\sqrt{10})}=3^{(\sqrt{5})^2-(\sqrt{2})^2}*3^{(\sqrt{7})^2-(\sqrt{10})^2}=3^{5-2}*3^{7-10}=3^3*3^{-3}=3^{3+(-3)}=3^0=1.[/tex]
