[tex]m(<A)+m(<B)+m(<C)=180\\x+20+2x+\frac{x-16}{2} =180|*2\\2x+40+4x+x-16=360\\7x=24=360\\7x=336\\[/tex]
[tex]x=\frac{336}{7} =48\\y=180-\frac{x-16}{2} \\y=180 -\frac{48-16}{2} \\y=180-\frac{32}{2} \\y=180-16 =164\\\\[/tex]
[tex]m(<A)=68\\m(<B)=96\\m(<C)=16\\m(<ACD)=164[/tex]