[tex]\it a)\ = \dfrac{1}{10}: \dfrac{1}{5}= \dfrac{1}{10}\cdot \dfrac{5}{1}= \dfrac{1}{2}\\ \\ \\ b)\ =\dfrac{6}{17}\cdot \Big(\dfrac{^{3)}3}{\ 4} +\dfrac{^{4)}2}{\ 3} \Big) =\dfrac{6}{17}\cdot\dfrac{17}{12}=\dfrac{1}{2} \\ \\ \\ c)\ = \dfrac{^{10)}6}{\ 17}+\dfrac{^{17)}1}{\ 10}=\dfrac{60+17}{170}=\dfrac{77}{170}[/tex]
