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calculați (x+3)²-(x-2)²​

Răspuns :

[tex] {x}^{2} + 6x + 9 - {x}^{2} + 4x - 4 = 10x + 5 = 5(2x + 1)[/tex]

[tex]\bf (x+3)^{2}-(x-2)^{2}=[/tex]

[tex]\bf [(x+3)-(x-2)]\cdot [(x+3)+(x-2)] =[/tex]

[tex]\bf [x+3-x+2]\cdot [x+3+x-2] =[/tex]

[tex]\bf (3+2)\cdot (2x+1) =[/tex]

[tex]\boxed{ \bf 5(2x+1)}[/tex]

Am folosit formula: a² - b² = (a+b)(a-b)