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[tex]g) 5,2+5,(2)-5,02-5,0(2)=\frac{52}{10} +\frac{52-5}{9} -\frac{502}{100} -\frac{502-50}{90} =[/tex]
[tex]=\frac{52}{10} +\frac{50}{9} -\frac{502}{100} -\frac{452}{90} =[/tex]
[tex]=^{90)} \frac{26}{5} +^{50)} \frac{50}{9} -^{9)} \frac{251}{50} -^{10)} \frac{226}{45} =[/tex]
[tex]=\frac{234+2500-2259-2260}{450} =[/tex]
[tex]=\frac{321}{450}[/tex]
