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17/5:(11/6 la puterea 2-27/9)

Răspuns :

[tex]\frac{\frac{17}{5}}{\left(\frac{11}{6}\right)^2-\frac{27}{9}}[/tex]

[tex]=\frac{17}{5\left(\left(\frac{11}{6}\right)^2-\frac{27}{9}\right)}[/tex]

[tex]=\frac{17}{5\left(\frac{11^2}{6^2}-\frac{27}{9}\right)}\\[/tex]

[tex]=\frac{17}{5\left(\frac{11^2}{6^2}-3\right)}[/tex]

[tex]\frac{11^2}{6^2}[/tex]

[tex]=\frac{17}{5\left(\frac{121}{36}-3\right)}[/tex]

[tex]=\frac{17}{5\cdot \frac{13}{36}}[/tex]

[tex]=\frac{17}{\frac{65}{36}}[/tex]

[tex]=\frac{17\cdot \:36}{65}[/tex]

[tex]=\frac{612}{65}[/tex]

Sper că te-am ajutat!

Succes!