2⁴•32²:64⁵•256⁻² = ?
Vom scrie fiecare factor ca o putere a lui 2
[tex]\it 32^2=(2^5)^2=2^{10}\\ \\ 64^5=(2^6)^5=2^{30}\\ \\ 256^{-2}=(2^8)^{-2}=2^{-16}[/tex]
[tex]\it Acum, avem:\\ \\ 2^4\cdot2^{10}:2^{30}\cdot2^{-16}=2^{4+6-30-16}=2^{-36}[/tex]
[tex]\it 2)\ Analog,\ folosind\ puterile\ lui\ 3, avem:\\ \\ 3^4:3^9\cdot3^{30}\cdot3^{-8}=3^{4-9+30-8}=3^{17}[/tex]