Răspuns:
Explicație:
16g Br2
nr. molecule Br2
-se afla nr. moli Br2 din 16g Br2
n= 16g : 80 . 2g/moli= 0,1 moli Br2
1mol Br2-------------6,023.10²³molecule Br2
0,1 moli -----------------------x
x= 0,1 . 6,023.10²³molecule = 0,6023.10²³molecule Br2
196g H2SO4
nr. molecule
MH2SO4=2+32+4.16=98------->98g/moli
n=196g : 98g/moli=2moli H2SO4
1mol H2SO4 --------------6,023.10²³molecule H2SO4
2moli-------------------------------y
y= 2 . 6,023.10²³= 12,046.10²³molecule H2SO4
90g H2O
nr. molecule
MH2O=2+16=18-------->18g/moli
n=90g : 18g/moli=5moli H2O
1mol H2O------------6,023.10²³molecule
5moli--------------------------z
z= 5 .6,023.10²³molecule=30,115.10²³molecule H2O
