Răspuns:
1.
A = [-3, 5)
B = [-4, +infinit)
C = (-infinit, 15)
D = [-2, 2]
E = [-2, 2]
F = (-infinit, -3]
G = (2, +infinit)
H = (0, 2)
I = (3, +infinit)
2.
AnB={-1, 0}
A\B={1, 2, 3}
B\A={-2, 4, 5}
AUB={-2,-1, 0, 1, 2, 3, 4, 5}
AnZ=A
BnN={0, 4, 5}
AUmultimea vidă = A
