Răspuns:
Explicație:
H2SO4
r.a.=2 : 1 :4
r.m.= 2 : 32 : 4.16
=2 : 32 : 64
= 1 : 16 : 32
compozitie procentuala prin masa moleculara
M= 2 + 32 + 64=98---------> 98g/moli
98g H2SO4---------2gH-------------32gS-------------64g O
100g-----------------------x------------------y------------------z
x=100.2 : 98=2,04% H
y= 100.32 : 98 =32,65% S
z= 100.64 : 98=65,31 % O
