1.
100% .................. 500kg impur
p% ....................... 300kg pur
= 60%
2.
80% ........................... 1300kg pur
100% ........................... m.impur = 1625 kg
3.
notam cu n = masa de fier + m = masa de sulf
7g amestec ..................... 100% impur
x g amestec pur ............ 95%
= 6,65 g amestec pur de fier si sulf
=> n + m = 6,65 g
m = 2n => n+2n = 6,65 => n = 2,22 g fier
=> m = 6,65 - 2,22 = 4,43 g sulf