Răspuns:
Explicație pas cu pas:
a) 2a(a-3b) = [tex]2a^{2}[/tex]-6ab
b) [tex]-2x^{2}( x^{2} -3x+1)=-4x^{4} +6x^{3} -2x[/tex]
c) 2a(a+b)-2b(a-b)-2([tex]a^{2}+b^{2}[/tex]) = [tex]2a^{2} +2ab-2ab+2b^{2} -2a^{2} -2b^{2}[/tex]=0
i)
[tex](2x+\sqrt{3} y)+(-4x+2\sqrt{3}y-1)-(3x+3\sqrt{3}y)-4= \\2x+\sqrt{3} y-4x+2\sqrt{3} y-1-3x-3\sqrt{3} y-4=-5x+3\sqrt{3}x-3\sqrt{3} y -5\\=-5x-5[/tex]
