Răspuns:
[tex]\sqrt{2^{2}*3} =2\sqrt{3}[/tex]
[tex]\sqrt{3^{4}*5} =3^{2}\sqrt{5}=9\sqrt{5}[/tex]
[tex]\sqrt{5^{6}*7} =5^{3}\sqrt{7} } =125\sqrt{7}[/tex]
[tex]\sqrt{11^{10}*2} =11^{5}\sqrt{10} }[/tex]
[tex]\sqrt{(-5)^{4}*7} =|(-5)^{2}|\sqrt{7} =25\sqrt{7}[/tex]
[tex]\sqrt{2^{2}*3^{2}*5} =2*3\sqrt{5} =6\sqrt{5}[/tex]
[tex]\sqrt{(-7)^{2}*101} =|-7|\sqrt{101} =7\sqrt{101}[/tex]
[tex]\sqrt{5^{4}*3^{2}*2 } =5^{2}*3\sqrt{2} =75\sqrt{2}[/tex]
a)
[tex]\sqrt{12} =\sqrt{2^{2}*3} =2\sqrt{3} \\\sqrt{18} =\sqrt{3^{2}*2} =3\sqrt{2} \\\sqrt{27}=\sqrt{3^{3}}=3\sqrt{3} \\\sqrt{32}=\sqrt{2^{5}}=4\sqrt{2} \\\sqrt{75} =\sqrt{5^{2}*3} =5\sqrt{3}[/tex]
b)
[tex]\sqrt{360} =\sqrt{6^{2}*10} =6\sqrt{10} \\\sqrt{192}=\sqrt{8^{2}*3}=8\sqrt{3}\\\sqrt{150}=\sqrt{5^{2}*6} =5\sqrt{6} \\\sqrt{288} =\sqrt{12^{2}*2} =12\sqrt{2}[/tex]
Explicație pas cu pas:
