[tex]\it (\overline{abcabc}+\overline{abc00}):(3\cdot\overline{abc})=\dfrac{\overline{abc000}+\overline{abc}+\overline{abc00}}{3\cdot\overline{abc}}=\dfrac{1000\cdot\overline{abc}+\overline{abc}+100\cdot\overline{abc}}{3\cdot\overline{abc}}=\\ \\ \\ =\dfrac{\overline{abc}\cdot(1000+1+100)}{3\cdo\overline{abc}}=\dfrac{\overline{abc}\cdot1101}{3\cdot\overline{abc}}=\dfrac{1101}{3}=367[/tex]
