la reactia 1 mol acid monoprotic si 1 mol baza monoacida => 1 mol H2O si se degaja cca. +57,27 kJ/mol.
Q.neutralizare = +57,27 kJ/mol H2O formata
1 mol apa .................... +57,27 kJ
n moli apa .................. 274,896 kJ
= 4,8 moli H2O
a moli 4,8 moli
HCl + NaOH --> NaCl + H2O
1 1
=> a = 1x4,8/1 = 4,8 moli HCl
Cm = n.moli/Vs, Vs = 300 mL = 0,3 L
=> Cm = a/0,3 = 4,8/0,3 = 16 L sol. HCl