Răspuns:
a
Explicație pas cu pas:
a.
[tex] {2}^{2 + 4 + 6} = {2}^{12} \\ [/tex]
b.
[tex] {5}^{1 + 2 + 3} = {5}^{6} [/tex]
c.
[tex] {3}^{8 + 12 + 10 + 4} = {3}^{34} [/tex]
h.
[tex] {2}^{1} \times {2}^{2} \times {2}^{3} = {2}^{1 + 2 + 3} = {2}^{6} [/tex]
i.
[tex] {2}^{10} \div {2}^{6 } = {2}^{10 - 6} = {2}^{4} [/tex]
o.
[tex] {2}^{5 \times 3} = {2}^{15} [/tex]
u.
[tex] {3}^{4 \times 7 \times 5 \times 2 } = {3}^{280} [/tex]
