Răspuns:
[tex]( {2}^{2} \times {2}^{3} \times {2}^{10} )^{4} \div ( {8}^{2}) ^{5} = \\ ({2}^{2 + 3 + 10} ) ^{4} \div ({8})^{2 \times 5} = \\ ( {2}^{15} ) ^{4} \div {8}^{10} = \\ ( {2})^{15 \times 4} \div ( {2}^{3}) {}^{10} = \\ {2}^{60} \div ({2})^{3 \times 10} = \\ {2}^{60} \div {2}^{30} = {2}^{30} [/tex]
sper că te-am ajutat!!!
