Explicație pas cu pas:
[tex]( {11}^{2011} \times {2}^{2010} ) \div {22}^{2010} = ( {11}^{2011} \times {2}^{2010} ) \div ( {11}^{2010} \times {2}^{2010} ) = 11 \times 1 = 11 \\ \\ {2}^{23 - 21 - 1} + {3}^{32 - 31 + 1} = {2}^{1} + {3}^{2} = 2 + 9 = 11[/tex]
