Răspuns:
[tex]10 \times ( { {9}^{2} }^{2} \div {3}^{8} + 2 \times ( ({2}^{30} \times {3}^{15} ) \div ( {2}^{29} \times {3}^{15) } + 1) = 10 \times ( { {3}^{2} }^{4} \div {3}^{8} + 2 \times (( {2}^{30 - 29} \times {3}^{15 - 15} ) + 1) = 10 \times ( {3}^{8} \div {3}^{8} + 2 \times (2 \times 1 + 1) = 10 \times (1 + 6)70[/tex]
