Răspuns:
Explicație pas cu pas:
[tex]0,0(6)=\dfrac{6}{90};~0,0(5)=\dfrac{5}{90};~0,0(6)-0,0(5)=\dfrac{6}{90}-\dfrac{5}{90}=\dfrac{1}{90}.\\0,(3)+8,(6)+1=\dfrac{3}{9}+8\dfrac{6}{9}+1=9+\dfrac{9}{9}=9+1=10.\\\dfrac{1}{90}:10=\dfrac{1}{90}*\dfrac{1}{10}=\dfrac{1}{900}.\\\sqrt{\dfrac{1}{900}}=\dfrac{1}{30}\\\dfrac{1}{30}*30=\dfrac{30}{30}=1.\\\dfrac{2b-a}{a}=1,~=>~2b-a=a,~=>~2b=2a,|:2,~=>~b=a,~=>~\dfrac{a}{b}=1.[/tex]
