Răspuns:
[tex] {2}^{8} \times {4}^{12} \times {8}^{32} \div {16}^{32} = \\ {2}^{8} \times ( {2}^{2} ) {}^{12} \times ( {2}^{3} ) {}^{32} \div ( {2}^{4} ) {}^{32} = \\ {2}^{8} \times {2}^{24} \times {2}^{96} \div {2}^{128} = \\ {2}^{32} \times {2}^{96} \div {2}^{128} = \\ {2}^{128} \div {2}^{128} = {2}^{0} [/tex]
sper că te-am ajutat!
