Răspuns:
Explicație:
1.
xkg ykg 486 kg
2Zn + O2 = 2 Zn O
2 . 65kg 32kg 2.81kg
x= 486. 130 : 162=390 kg Zn
n= m: M
n= 390 kg : 65kg/kmoli= 6 kmoli Zn
y= 486 . 32 : 162= 96 Kg O
n= 96kg : 32kg/kmoli=3 kmoli O2
2.
-se afla nr. de moli de MgO care rezulta
rqandament= mp.100 : mt
mp= randam . mt : 100
mp= 80. 10 : 100=8 moli MgO
xmoli ymoli 8 moli
2Mg + O2 = 2 MgO
2moli 1mol 2moli
x= 2 . 8 : 2=8 moli Mg
m= n . M
m= 8 moli . 24g/moli= 192g Mg
y= 8 .1 : 2= 4moli O2
m= 4moli . 32g/moli= 128 g O
3.
-se afla md sol. de HCl
md= c.ms : 100
md= 1095 . 20 : 100= 219 g HCl
xg 219g yg zg
Zn + 2 HCl = ZnCl2 + H2
65g 2.36,5g 136g 2g
x= 219. 65 : 73=195 g Zn
y= 219 . 136 : 73= 408 g ZnCl2
n= 408g : 136 g/moli= 3moli ZnCl2
z= 219.2 : 73= 6 g H
n= 6g : 2g/moli= 3 moli H2
MZnO= 65 + 16= 81------> 81g
MHCl= 1+ 35,5=36,5 ------> 36,5g.moli
MZnCl2= 65 + 2.35.5= 136------> 136g/moli
