Răspuns: 1
Explicație pas cu pas:
Salutare!
[tex]\bf [2^{12} \cdot 2^{18} +5^{70}:5^{10}-(3^{25})^{2}]:[4^{2} \cdot 2^{3}\cdot 2^{23} +(5^{15})^{2^{2}}-(3^{2})^{5^{2}}]=[/tex]
[tex]\bf [2^{12+18} +5^{70-10}-3^{25\cdot 2}]:[(2^{2})^{2} \cdot 2^{3}\cdot 2^{23} +(5^{15})^{4}-(3^{2})^{25}]=[/tex]
[tex]\bf (2^{30} +5^{60}-3^{50}):(2^{2\cdot2} \cdot 2^{3}\cdot 2^{23} +5^{15\cdot 4}-3^{2\cdot 25})=[/tex]
[tex]\bf (2^{30} +5^{60}-3^{50}):(2^{4} \cdot 2^{3}\cdot 2^{23} +5^{60}-3^{50})=[/tex]
[tex]\bf (2^{30} +5^{60}-3^{50}):(2^{4+3+23} +5^{60}-3^{50})=[/tex]
[tex]\bf (2^{30} +5^{60}-3^{50}):(2^{30} +5^{60}-3^{50})=[/tex]
[tex]\boxed{\bf 1}[/tex]
Formule folosite
(aⁿ)ᵇ = aⁿ ˣ ᵇ
aⁿ · aᵇ = (a)ⁿ ⁺ ᵇ
aⁿ : aᵇ = (a)ⁿ ⁻ ᵇ
==pav38==
