Răspuns:
Explicație pas cu pas:
e) 10·{24²:576 + 3·[(3²·2)¹⁵:(3²⁹·2¹⁵)+1²¹]}:13 =
= 10·{576:576 +3·[(3²ˣ¹⁵·2¹⁵):(3²⁹·2¹⁵)+1]}:13 =
= 10·{1+3·(3+1)}:13 = 10·(1+3·4):13 = 10·13:13 = 10
f) 2¹⁰⁰:[2⁵⁰·2⁴⁸+(2¹⁰·2¹⁵)⁵:2²⁷+(5⁷⁶:5⁷⁵-3)⁹⁰·2⁸+2⁹⁸] =
= 2¹⁰⁰:[2⁵⁰⁺⁴⁸+2⁽¹⁰⁺¹⁵⁾⁵⁻²⁷ +(5⁷⁶⁻⁷⁵-3)⁹⁰·2⁸+2⁹⁸] =
= 2¹⁰⁰:[2⁹⁸+2⁹⁸+2⁹⁸+2⁹⁸] = 2¹⁰⁰:[2⁹⁸·4] = 2¹⁰⁰:[2⁹⁸⁺²] =
= 2¹⁰⁰:2¹⁰⁰ = 1
