Răspuns:
A=
[tex] ({25}^{27} ) \div {(16 + 9})^{26} - {(1 + 0 + 1)}^{4} = {25}^{27} \div {25}^{26} - 16 = 25 - 16 = 9[/tex]
B=
[tex]128 - 11 \times (91 - 5 \times22 - 5 \times (1600 - 1599)) + {(9 - 8})^{2017} = 128 - 11 \times (91 - 5 \times 22 - 5 \times 1) + {1}^{2017} = 128 - 11 \times (91 - 5 \times 22 - 5) + 1 = 128 - 11 \times (91 - 5 \times 17 + 1 = 128 - 11 \times (91 - 85) + 1 = 128 - 11 \times 6 + 1 = 128 - 66 + 1 = 62 + 1 = 63[/tex]
B>A
