[tex]\displaystyle\bf\\\Delta T=313^oK-20^oC=\\\\=313^oK-(273+20)^oK=\\\\=313^oK-293^oK=20^oK\\\\\Delta T=20^oK\\\\c=4180\frac{J}{Kg\cdot K} \\\\m=100~g=0,1~Kg\\\\Folosim~formula:\\\\c=\frac{Q}{m\Delta T}~~\implies~~Q=mc\Delta T\\\\\\Rezolvare:\\\\Q=mc\Delta T=0,\!1Kg\times4180\frac{J}{Kg\cdot K}\times20^oK\\\\Q=0,\!1\times4180\times20=418\times20=8360~J\\\\\boxed{\bf Q=8360~J}[/tex]
