a) 798 345 + 12 462 = 810 807
b) 63 232 - 1 121 = 62 111
c) 800 692 - 400 372 =400 320
d) 621 720 + 365 268 = 986 988
e) 798 678 - 324 522 = 474,156
f) 677 864 - 123 453 = 554,411
2. a= 675 956 - 231 434
a= 444,522
a= 342 215 + 21 053
a= 363,268
3. a - (102 340 + 222) = 436 228
a - 102 562 = 436 228
a = 436 228 + 102 562
a= 538 790
4. numere consecutive : 121 324 , 121 323 , 121 322
suma numerelor = 121 324 + 121 323 + 121 322 =363,969
5. 957 768 - 221 446 = 736,322
micsoreaza inseamna scadere.
6.I transport x
II transport x+21 010
III transport x inmultit cu 2 + 4047
toate trebuie sa le egalam cu 36 993
x + x + 21 010 + 2x + 4047 = 36 993 <=> 2x+ 21 010 + 2x + 4047 = 36 993 <=> 4x + 25 057 36 993 <=> 4x = 36 993 - 25 057 <=> 4x= 11,936 <=> x= 2,984
