Salut!
Exercitiul 4:
[tex]\frac{11}{2\sqrt{6}-\sqrt{2}}[/tex] = [tex]\frac{11(2\sqrt{6}-\sqrt{2})}{22} = \frac{2\sqrt{6}-\sqrt{2}}{2} = \sqrt{6} - \sqrt{2}[/tex]
[tex]\frac{-2}{\sqrt{9}-\sqrt{5} } = \frac{-2(\sqrt{9}+\sqrt{5})}{4} = \frac{\sqrt{9}+\sqrt{5}}{-2} = \frac{3-\sqrt{5} }{-2}[/tex]
Asta e cum am rezolvat eu....
