180g 92g
CH3COOH + HOC2H5 <==> CH3COOC2H5 + H2O
60 46
=> CH3COOH = 180/60 = 3
=> C2HOH = 92/46 = 2
=> CH3COOH este in exces , deci calculele le vom face fata de etanol.
92g m g
CH3COOH + HOC2H5 <==> CH3COOC2H5 + H2O
46 88
=> m = 92x88/46 = 176 g ester obtinut teoretic la 100% ... dar la 90% cat s-ar fi obtinut practic
100% ..................... 176g ester
90% ....................... Cp = 158,4 g ester