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[tex](2 \times + 1) {?}^{2} - ( \times - 3 {?}^{2} [/tex]


Răspuns :

[tex](2x+1)^{2} -(x-3)^{2} =(4x^{2} +4x+1)-(x^{2} -6x+9)=\\4x^{2} +4x+1-x^{2} +6x-9=\\3x^{2} +10x-8[/tex]