Răspuns:
l.
1) 2H3PO4 + 3Mg(OH)2=> Mg3(PO4)2+6H2O
II
1) MgO + H2O => Mg(OH)2
2) 2Fe +3Cl2=> 2FeCl3
3) CO2 + H2O => H2CO3
4) N2+3H2=> 2NH3
5) H2+ I2=> 2HI
6) 4Na+ O2=> 2Na2O
III.
2moli 3moli
2Fe + 3Cl2 => 2FeCl3
10moli xmoli
x=10×3/2=15moliCl2
IV.
100gFe........56g Fe pur
600gFe.......ygFe pur
y=600×56/100=336gFe pur
MMFe56g/mol
MFeCl3=56+3×35,5=162,5g/mol
2×56g 2×162,5g
2Fe + 3Cl2 => 2FeCl3
336g m=?
m=336×2×162,5/2×56=calculează
