Răspuns:
1. MH2=2×AH=2×1=2g/kmoli
[tex]n = \frac{m}{m \: mare} \\ m = n \times m \: mare = 10kmol \times \frac{2g}{kmol} = 20g[/tex]
2. 284 kg P2O5= 284000g
MP2O5=AP×2+AO×5= 2×31+5×16= 62+80= 142g/mol
[tex]n = \frac{284000g}{ 142g/mol } = 2000moli[/tex]