Răspuns:
se inmultesc termenii pe diagonala
la impartirea a doua fractii a doua fractie se intoarce si se face operatia de inmultire
x·0,(12)=(³⁾1/2-1/6)·(3/2+6/5·5/4)
0,(12)=12/99=4/33
4x/33=(3/6-1/6)·(3/2+3/2)
4x/33=2/6·6/4 la inmultire se simplifica termenii pe diagonala
4x/33=1/2
2·4x=33
8x=33=>x=33/8=4,125
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[·(1·9+7)/9·3/8]·(²⁾11/15-1/30)=x·14/5
(16/9·3/8)·(22/30-1/30)=14x/5
2/3·21/30=14x/5
42/60=14x/5
14x·60=42·5
840x=210
x=210/840
x=0,25
