Explicație pas cu pas:
1. (3¹×2²⁰⁰⁴-2²⁰⁰⁵)÷4¹⁰⁰¹=(3¹×2²⁰⁰⁴-2²⁰⁰⁵)÷(2²)¹⁰⁰¹=(3¹×²⁰⁰⁴-2²⁰⁰⁵)÷2²⁰⁰²=3×2²⁰⁰⁴÷2²⁰⁰²-2²⁰⁰⁵÷2²⁰⁰²=3×2²-2³=3×4-8=12-8=4
2.
[tex] {2}^{ x + 3} \times 2 {}^{x} = 256 = 2 {}^{x} \times 2 {}^{3} \times 2 {}^{x} = 256 = > 4x {}^{2} {}^{} \times 8 = 256 = > 4x {}^{2} = 256 \div 8 = 32 = > x {}^{2} =32 \div 4 = 8 = \sqrt{8} = 2 \sqrt{2} \\ \\ 2 {}^{x + 3} \times 2 {}^{x} = 256 = > 2 { }^{x + 3 + x} = 256 = > 2 {}^{2x + 3} = 256 = > 2 {}^{2x} \times 2 {}^{3} = 256 = > 2 {}^{2x} = 256 \div 8 = 32 = > 2 {}^{2x} = 2 {}^{5} = 2x = 5 = > x = \frac{5}{2} [/tex]
Cred că, a doua variantă este corectă!
