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sa se afle numerele x,y,z eQ stiind ca sunt direct proportionale cu 3,4,5 si 1/x + 1/y +1/z=47/80 URGENTTT VAAA ROGGG


Răspuns :

[tex] \frac{x}{3} = \frac{y}{4} = \frac{z}{5} = k[/tex]

X=3k

Y=4k

Z=5k

1\3k+1\4k+1\5k=47\80

20\60k+15\60k+12\60k=47\80

47\20k=47\80

K=4

=>x=12

Y=16

Z=20